2[x-3(x+2)-4]=6

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Solution for 2[x-3(x+2)-4]=6 equation: 


Simplifying
2[x + -3(x + 2) + -4] = 6

Reorder the terms:
2[x + -3(2 + x) + -4] = 6
2[x + (2 * -3 + x * -3) + -4] = 6
2[x + (-6 + -3x) + -4] = 6

Reorder the terms:
2[-6 + -4 + x + -3x] = 6

Combine like terms: -6 + -4 = -10
2[-10 + x + -3x] = 6

Combine like terms: x + -3x = -2x
2[-10 + -2x] = 6
[-10 * 2 + -2x * 2] = 6
[-20 + -4x] = 6

Solving
-20 + -4x = 6

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '20' to each side of the equation.
-20 + 20 + -4x = 6 + 20

Combine like terms: -20 + 20 = 0
0 + -4x = 6 + 20
-4x = 6 + 20

Combine like terms: 6 + 20 = 26
-4x = 26

Divide each side by '-4'.
x = -6.5

Simplifying
x = -6.5

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